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Copy pathConstruct Binary Tree from PreOrder and PostOrder Traversal
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57 lines (48 loc) · 1.65 KB
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Construct Binary Tree from PreOrder and PostOrder Traversal
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57 lines (48 loc) · 1.65 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode constructFromPrePost(int[] preorder, int[] postorder) {
return construct(preorder,postorder);
}
public TreeNode construct(int[] preorder,int[] postorder){
if(preorder.length == 0 && postorder.length == 0){
return null;
}
TreeNode node = new TreeNode();
node.val = preorder[0];
if(preorder.length == 1 && postorder.length == 1 ){
node.left = null;
node.right = null;
return node;
}
int splitFactor = preorder[1];
int index = -1;
for(int i=0;i<postorder.length;i++){
if(postorder[i] == splitFactor){
index = i;
break;
}
}
//splitting both the arrays into two and passing
int[] postordFirst = Arrays.copyOfRange(postorder,0,index+1);
int[] postordSec = Arrays.copyOfRange(postorder,index + 1,postorder.length -1);
int preFirst[] = Arrays.copyOfRange(preorder,1,postordFirst.length + 1);
int preSecond[] = Arrays.copyOfRange(preorder,postordFirst.length + 1,preorder.length);
node.left = construct(preFirst,postordFirst);
node.right = construct(preSecond,postordSec);
return node;
}
}