SQL-ChallengesKhanAcademy/challenge6-TheWordiestAuthor.sql at main · AndreaDev14/SQL-ChallengesKhanAcademy · GitHub

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/* Challenge: The wordiest author*/

CREATE TABLE books (
    id INTEGER PRIMARY KEY AUTOINCREMENT,
    author TEXT,
    title TEXT,
    words INTEGER);

INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Philosopher's Stone", 79944);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Chamber of Secrets", 85141);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Prisoner of Azkaban", 107253);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Goblet of Fire", 190637);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Order of the Phoenix", 257045);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Half-Blood Prince", 168923);
INSERT INTO books (author, title, words)
    VALUES ("J.K. Rowling", "Harry Potter and the Deathly Hallows", 197651);

INSERT INTO books (author, title, words)
    VALUES ("Stephenie Meyer", "Twilight", 118501);
INSERT INTO books (author, title, words)
    VALUES ("Stephenie Meyer", "New Moon", 132807);
INSERT INTO books (author, title, words)
    VALUES ("Stephenie Meyer", "Eclipse", 147930);
INSERT INTO books (author, title, words)
    VALUES ("Stephenie Meyer", "Breaking Dawn", 192196);

INSERT INTO books (author, title, words)
    VALUES ("J.R.R. Tolkien", "The Hobbit", 95022);
INSERT INTO books (author, title, words)
    VALUES ("J.R.R. Tolkien", "Fellowship of the Ring", 177227);
INSERT INTO books (author, title, words)
    VALUES ("J.R.R. Tolkien", "Two Towers", 143436);
INSERT INTO books (author, title, words)
    VALUES ("J.R.R. Tolkien", "Return of the King", 134462);


/* Step 1
- In this first step, select all the authors who have written more than 1 million words, using GROUP BY and HAVING. Your results table should include the 'author'
and their total word count as a 'total_words' column. */
SELECT author, SUM(words) AS total_words FROM books
GROUP BY author HAVING total_words > 1000000;

/* Step 2
- Now select all the authors that write more than an average of 150,000 words per book.
- Your results table should include the 'author' and average words as an 'avg_words' column. */
SELECT author, AVG(words) AS avg_words FROM books
 GROUP BY author HAVING avg_words > 150000;