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mergeSort.java
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46 lines (43 loc) · 920 Bytes
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/**
利用归并排序求逆序对的数目1
*/
class Solution{
static int[] tmp;
static int[] nums;
public static void main(String[] args) {
nums = new int[]{7,3,2,6,0,1,5,4};
tmp = new int[nums.length];
int ans = mergeSort(0,nums.length - 1);
System.out.println(ans);
for(int i = 0;i<nums.length;i++) System.out.print(nums[i] + " ");
System.out.println();
}
public static int mergeSort(int l,int r){
if(l>=r) return 0;
int m = l + (r-l)/2;
int res = mergeSort(l,m) + mergeSort(m+1,r);
int i = l;
int j = m+1;
for(int k = l;k<=r;k++){
tmp[k] = nums[k];
}
for(int k = l;k<=r;k++){
if(i == m + 1){
nums[k] = tmp[j];
j++;
}
else if(j == r + 1 || tmp[i] <= tmp[j]){
nums[k] = tmp[i];
i++;
}
else{
res+=m-i+1;
nums[k] = tmp[j];
j++;
}
}
for(int k = l;k<=r;k++) System.out.print(tmp[k] + " ");
System.out.println();
return res;
}
}