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unknowning-eoking
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� Study: 2차원 동전 뒤집기
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# 앞 = 검은색 = 0, 뒤 = 흰색 = 1
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# 초기 -> 목표
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# 최소니까 DP?
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# 시간복잡도가 상관없을 거 같음
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def solution(beginning, target):
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n = len(beginning)
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matrix = [[0 for _ in range(n)] for _ in range(n)]
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coutn = 0
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# 한 행 바꿨을 때 target이랑 같으면 그 행을 건드리면 안되니까 빼버린다 생각
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for i in range(n):
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if beginning[i] == target[i]:
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beginning = beginning.pop(i)
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target = target.pop(i)
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for j in range(n):
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col_b = [beginning[i][j] for i in range(n)]
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col_t = [beginning[i][j] for j in range(n)]
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if col_b == colt_t:
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beginning = beginning[i]

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