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Copy path543_Diameter_Of_Binary_Tree.py
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35 lines (26 loc) · 1008 Bytes
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int:
if root is None:
return 0
# We use a list so diameter is pass by reference
diameter = []
diameter.append(0)
self.dfs(root, diameter)
return diameter[0]
def dfs(node, diameter):
if node.left is None and node.right is None:
return 0
left_height, right_height = 0, 0
if node.left is not None:
left_height = 1 + self.dfs(node.left, diameter)
if node.right is not None:
right_height = 1 + self.dfs(node.right, diameter)
if left_height + right_height > diameter[0]:
diameter[0] = left_height + right_height
return max(left_height, right_height)