diff --git a/src/3700-3799/3754.cpp b/src/3700-3799/3754.cpp
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+/*
+Tags
+level-easy
+math
+
+Problem Description
+3754. Concatenate Non-Zero Digits and Multiply by Sum I
+
+You are given an integer n.
+Form a new integer x by concatenating all the non-zero digits of n in their original order. If there are no non-zero digits, x = 0.
+Let sum be the sum of digits in x.
+Return an integer representing the value of x * sum.
+
+Example 1:
+Input: n = 10203004
+Output: 12340
+Explanation:
+The non-zero digits are 1, 2, 3, and 4. Thus, x = 1234.
+The sum of digits is sum = 1 + 2 + 3 + 4 = 10.
+Therefore, the answer is x * sum = 1234 * 10 = 12340.
+
+Example 2:
+Input: n = 1000
+Output: 1
+Explanation:
+The non-zero digit is 1, so x = 1 and sum = 1.
+Therefore, the answer is x * sum = 1 * 1 = 1.
+
+Constraints:
+0 <= n <= 10^9
+*/
+
+#include <iostream>
+#include <vector>
+#include <string>
+#include <algorithm>
+#include <numeric>
+#include <cmath>
+#include <queue>
+#include <stack>
+#include <set>
+#include <map>
+#include <unordered_map>
+#include <unordered_set>
+#include <sstream>
+#include <limits>
+#include <iomanip>
+#include <functional>
+#include <cstring>
+#include <climits>
+#include "../core/core.h"
+using namespace std;
+
+class Solution
+{
+public:
+	long long sumAndMultiply(int n)
+	{
+		string value = to_string(n);
+		long long sum = 0;
+		long long x = 0;
+		for (auto& c : value)
+		{
+			int d = c - '0';
+			sum += d;
+			if (d > 0)
+			{
+				x = x * 10 + d;
+			}
+		}
+
+		return x * sum;
+	}
+};
+
+int main()
+{
+	int n;
+	cin >> n;
+	Solution sol;
+	long long result = sol.sumAndMultiply(n);
+	cout << result << "\n";
+	return 0;
+}
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diff --git a/tests/3700-3799/3754.txt b/tests/3700-3799/3754.txt
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+Test Case 1:
+Input:
+10203004
+Output:
+12340
+
+Test Case 2:
+Input:
+1000
+Output:
+1
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