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resources/links/Angular resolution.md
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It seems that in astronomy, there is a relationship between the image resolution $\theta$ and the wavelength $\lambda$ giving by
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- $$\theta = 1.22 \frac{\lambda} {D}$$
+**The Cauchy-Schwarz Inequality**
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+$$\left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right)$$
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- $$\int_\Omega \nabla u \cdot \nabla v~dx = \int_\Omega fv~dx$$
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- Where $D$ is the diameter of the telescope.
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- to get better resolution (small $\theta$), we need:
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