Update Angular resolution.md

Author: eahussein

resources/links/Angular resolution.md

@@ -13,7 +13,7 @@
 
 It seems that in astronomy, there is a relationship between the image resolution $\theta$ and the wavelength
 
-$\lambda$ giving by $$ \theta = 1.22 \frac{\lambda} {D} $$
+$$ \lambda$ giving by $$ \theta = 1.22 \frac{\lambda} {D} $$
 
 - Where $D$ is the diameter of the telescope.
 - to get better resolution (small $\theta$), we need: