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103차 3번 문제풀이
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"""
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dp[1] = 1
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dp[2] = 2
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dp[3] = 3
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dp[4] = 5
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dp[5] = dp[n-1] + dp[n-2]
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"""
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def solution(n):
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dp = [0] * (n + 1)
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dp[1] = 1
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dp[2] = 2
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for i in range(3, n + 1):
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dp[i] = (dp[i-2] + dp[i-1]) % 1000000007
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return dp[n]

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