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| 1 | +{ |
| 2 | + "cells": [ |
| 3 | + { |
| 4 | + "cell_type": "markdown", |
| 5 | + "metadata": {}, |
| 6 | + "source": [ |
| 7 | + "Muhammad Abdullah\n", |
| 8 | + "\n", |
| 9 | + "B22F0577AI054\n", |
| 10 | + "\n", |
| 11 | + "AI BLUE\n", |
| 12 | + "\n", |
| 13 | + "LAB TASK:7\n", |
| 14 | + "\n", |
| 15 | + "Submitted To: Mam Anila Habib" |
| 16 | + ] |
| 17 | + }, |
| 18 | + { |
| 19 | + "cell_type": "markdown", |
| 20 | + "metadata": {}, |
| 21 | + "source": [ |
| 22 | + "Task:1\n", |
| 23 | + "\n", |
| 24 | + " Program to determine the quadrant of a point in a 2D plane\n", |
| 25 | + "\n", |
| 26 | + "Using of 4 if conditions:" |
| 27 | + ] |
| 28 | + }, |
| 29 | + { |
| 30 | + "cell_type": "code", |
| 31 | + "execution_count": 1, |
| 32 | + "metadata": {}, |
| 33 | + "outputs": [ |
| 34 | + { |
| 35 | + "name": "stdout", |
| 36 | + "output_type": "stream", |
| 37 | + "text": [ |
| 38 | + "The point is in the first quadrant\n" |
| 39 | + ] |
| 40 | + } |
| 41 | + ], |
| 42 | + "source": [ |
| 43 | + "x = float(input(\"Enter the x-coordinate: \"))\n", |
| 44 | + "y = float(input(\"Enter the y-coordinate: \"))\n", |
| 45 | + "\n", |
| 46 | + "if x > 0 and y > 0:\n", |
| 47 | + " print(\"The point is in the first quadrant\")\n", |
| 48 | + "if x < 0 and y > 0:\n", |
| 49 | + " print(\"The point is in the second quadrant\")\n", |
| 50 | + "if x < 0 and y < 0:\n", |
| 51 | + " print(\"The point is in the third quadrant\")\n", |
| 52 | + "if x > 0 and y < 0:\n", |
| 53 | + " print(\"The point is in the fourth quadrant\")" |
| 54 | + ] |
| 55 | + }, |
| 56 | + { |
| 57 | + "cell_type": "markdown", |
| 58 | + "metadata": {}, |
| 59 | + "source": [ |
| 60 | + "Result:\n", |
| 61 | + "\n", |
| 62 | + "In this program, we use four if conditions to determine the quadrant of a point in a 2D plane based on its x and y coordinates. Each if condition checks a specific combination of x and y values to determine the quadrant in which the point lies." |
| 63 | + ] |
| 64 | + }, |
| 65 | + { |
| 66 | + "cell_type": "markdown", |
| 67 | + "metadata": {}, |
| 68 | + "source": [ |
| 69 | + "Task:2\n", |
| 70 | + "\n", |
| 71 | + "Write a program of nested if conditions \n", |
| 72 | + "\n", |
| 73 | + "Program to determine the quadrant of a point in a 2D plane using nested if conditions" |
| 74 | + ] |
| 75 | + }, |
| 76 | + { |
| 77 | + "cell_type": "code", |
| 78 | + "execution_count": null, |
| 79 | + "metadata": {}, |
| 80 | + "outputs": [], |
| 81 | + "source": [ |
| 82 | + "x = float(input(\"Enter the x-coordinate: \"))\n", |
| 83 | + "y = float(input(\"Enter the y-coordinate: \"))\n", |
| 84 | + "\n", |
| 85 | + "if x > 0:\n", |
| 86 | + " if y > 0:\n", |
| 87 | + " print(\"The point is in the first quadrant\")\n", |
| 88 | + " if y < 0:\n", |
| 89 | + " print(\"The point is in the fourth quadrant\")\n", |
| 90 | + "if x < 0:\n", |
| 91 | + " if y > 0:\n", |
| 92 | + " print(\"The point is in the second quadrant\")\n", |
| 93 | + " if y < 0:\n", |
| 94 | + " print(\"The point is in the third quadrant\")" |
| 95 | + ] |
| 96 | + }, |
| 97 | + { |
| 98 | + "cell_type": "markdown", |
| 99 | + "metadata": {}, |
| 100 | + "source": [ |
| 101 | + "Result:\n", |
| 102 | + "\n", |
| 103 | + "In this program, we use nested if conditions to determine the quadrant of a point in a 2D plane. The outer if conditions check the sign of the x-coordinate, and the inner if conditions check the sign of the y-coordinate to determine the quadrant." |
| 104 | + ] |
| 105 | + }, |
| 106 | + { |
| 107 | + "cell_type": "markdown", |
| 108 | + "metadata": {}, |
| 109 | + "source": [ |
| 110 | + "Task:3\n", |
| 111 | + "\n", |
| 112 | + "Program that determines the quadrant of a point based on its x and y coordinates using if-else statements:\n" |
| 113 | + ] |
| 114 | + }, |
| 115 | + { |
| 116 | + "cell_type": "code", |
| 117 | + "execution_count": null, |
| 118 | + "metadata": {}, |
| 119 | + "outputs": [], |
| 120 | + "source": [ |
| 121 | + "\n", |
| 122 | + "\n", |
| 123 | + "x = float(input(\"Enter the x-coordinate of the point: \"))\n", |
| 124 | + "y = float(input(\"Enter the y-coordinate of the point: \"))\n", |
| 125 | + "\n", |
| 126 | + "if x > 0:\n", |
| 127 | + " if y > 0:\n", |
| 128 | + " print(\"The point is in the first quadrant\")\n", |
| 129 | + " else:\n", |
| 130 | + " print(\"The point is in the fourth quadrant\")\n", |
| 131 | + "else:\n", |
| 132 | + " if y > 0:\n", |
| 133 | + " print(\"The point is in the second quadrant\")\n", |
| 134 | + " else:\n", |
| 135 | + " print(\"The point is in the third quadrant\")" |
| 136 | + ] |
| 137 | + }, |
| 138 | + { |
| 139 | + "cell_type": "markdown", |
| 140 | + "metadata": {}, |
| 141 | + "source": [ |
| 142 | + "Result:\n", |
| 143 | + "\n", |
| 144 | + "In this program, the user inputs the x and y coordinates of a point. The program then uses nested if-else statements to determine the quadrant in which the point lies based on the signs of its x and y coordinates. The output indicates the quadrant in which the point is located." |
| 145 | + ] |
| 146 | + }, |
| 147 | + { |
| 148 | + "cell_type": "markdown", |
| 149 | + "metadata": {}, |
| 150 | + "source": [ |
| 151 | + "Task:4\n", |
| 152 | + "\n", |
| 153 | + " Python program that uses nested if-else statements to determine the quadrant in which a point lies based on its x and y coordinates:" |
| 154 | + ] |
| 155 | + }, |
| 156 | + { |
| 157 | + "cell_type": "code", |
| 158 | + "execution_count": null, |
| 159 | + "metadata": {}, |
| 160 | + "outputs": [], |
| 161 | + "source": [ |
| 162 | + "# Input x and y coordinates\n", |
| 163 | + "x = float(input(\"Enter the x-coordinate: \"))\n", |
| 164 | + "y = float(input(\"Enter the y-coordinate: \"))\n", |
| 165 | + "\n", |
| 166 | + "# Nested if-else statements to determine the quadrant\n", |
| 167 | + "if x > 0:\n", |
| 168 | + " if y > 0:\n", |
| 169 | + " print(\"The point is in the first quadrant\")\n", |
| 170 | + " else:\n", |
| 171 | + " print(\"The point is in the fourth quadrant\")\n", |
| 172 | + "else:\n", |
| 173 | + " if y > 0:\n", |
| 174 | + " print(\"The point is in the second quadrant\")\n", |
| 175 | + " else:\n", |
| 176 | + " print(\"The point is in the third quadrant\")" |
| 177 | + ] |
| 178 | + }, |
| 179 | + { |
| 180 | + "cell_type": "markdown", |
| 181 | + "metadata": {}, |
| 182 | + "source": [ |
| 183 | + "Result:\n", |
| 184 | + "\n", |
| 185 | + "We first input the x and y coordinates of a point.\n", |
| 186 | + "The program then uses nested if-else statements to check the signs of x and y to determine the quadrant in which the point lies.\n", |
| 187 | + "Depending on the conditions, it will output the quadrant in which the point is located." |
| 188 | + ] |
| 189 | + } |
| 190 | + ], |
| 191 | + "metadata": { |
| 192 | + "kernelspec": { |
| 193 | + "display_name": "Python 3", |
| 194 | + "language": "python", |
| 195 | + "name": "python3" |
| 196 | + }, |
| 197 | + "language_info": { |
| 198 | + "codemirror_mode": { |
| 199 | + "name": "ipython", |
| 200 | + "version": 3 |
| 201 | + }, |
| 202 | + "file_extension": ".py", |
| 203 | + "mimetype": "text/x-python", |
| 204 | + "name": "python", |
| 205 | + "nbconvert_exporter": "python", |
| 206 | + "pygments_lexer": "ipython3", |
| 207 | + "version": "3.12.0" |
| 208 | + } |
| 209 | + }, |
| 210 | + "nbformat": 4, |
| 211 | + "nbformat_minor": 2 |
| 212 | +} |
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