字句解析器の例外時にstrの内容を出力

Author: PANFACTORY

src/lexer.h

@@ -73,6 +73,7 @@ namespace JsonParser {
                 }
                 str = str.substr(0, str.find_last_not_of(" \f\t\v\r\n") + 1);
                 if (!std::regex_match(str, std::regex("-?(0|[1-9]\\d*)(\\.\\d+)?(e[-+](0|[1-9]\\d*)(\\.\\d+)?)?"))) {
+                    std::cout << str << std::endl;
                     throw std::runtime_error("At LexicalAnalyzer(): \"str\" is not a number.");
                 }
                 chs.push_back(str);
@@ -90,6 +91,7 @@ namespace JsonParser {
                 }
                 str = str.substr(0, str.find_last_not_of(" \f\t\v\r\n") + 1);
                 if (str != "true" && str != "false" && str != "null") {
+                    std::cout << str << std::endl;
                     throw std::runtime_error("At LexicalAnalyzer(): \"str\" is neither true, false nor null.");
                 }
                 chs.push_back(str);