docs, urls namespace

Author: willmcgugan

README.rst

@@ -6,3 +6,5 @@ Amazon S3 cloud storage.
 
 As a PyFilesystem concrete class, S3FS allows you to work with S3 in the
 same as any other supported filesystem.
+
+`Documentation <http://fs-s3fs.readthedocs.io/en/latest/>`__

docs/index.rst

@@ -34,14 +34,17 @@ There are two options for constructing a :ref:`s3fs` instance. The simplest way
 is with an *opener*, which is a simple URL like syntax. Here is an example::
 
     from fs import open_fs
-    s3fs = S3FS('s3://mybucket/')
+    s3fs = open_fs('s3://mybucket/')
 
 For more granular control, you may import the S3FS class and construct
 it explicitly::
 
     from fs_s3fs import S3FS
     s3fs = S3FS('mybucket')
 
+See :class:`~fs_s3fs.S3FS` for other arguments you may pass to the
+constructor.
+
 
 Authentication
 ==============

fs_s3fs/_s3fs.py

@@ -376,6 +376,19 @@ def _info_from_object(self, obj, namespaces):
                     value = datetime_to_epoch(value)
                 s3info[name] = value
 
+        if 'urls' in namespaces:
+            url = self.client.generate_presigned_url(
+                ClientMethod='get_object',
+                Params={
+                    'Bucket': self._bucket_name,
+                    'Key': key
+                }
+            )
+            info['urls'] = {
+                'download': url
+            }
+
+
         return info
 
     def getinfo(self, path, namespaces=None):

fs_s3fs/_version.py

@@ -1 +1 @@
-__version__ = "0.1.1"
+__version__ = "0.1.2a0"

setup.py

@@ -24,7 +24,7 @@
 
 REQUIREMENTS = [
     "boto3~=1.4.5",
-    "fs==2.0.7",
+    "fs~=2.0.7",
     "six~=1.10.0"
 ]