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437.cpp
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62 lines (57 loc) · 1.66 KB
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int dfs(TreeNode* root, int sum){
if(!root)
return 0;
return ((root->val == sum)?1:0) + dfs(root->left, sum - root->val) + dfs(root->right, sum - root->val);
}
int pathSum(TreeNode* root, int sum) {
if(!root) return 0;
return dfs(root,sum) + pathSum(root->left,sum) + pathSum(root->right,sum);
}
};
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
unordered_map<int,int> ump;
int dfs(TreeNode* root, int sum, int prev){
if(!root)
return 0;
int curr = prev + root->val;
ump[curr]++;
int left = dfs(root->left,sum,curr);
int right = dfs(root->right,sum,curr);
int res = left + right;
ump[curr]--;
if(ump.count(curr-sum))
res += ump[curr-sum];
return res;
}
int pathSum(TreeNode* root, int sum) {
ump[0] = 1;
if(!root)
return 0;
return dfs(root,sum,0);
}
};