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Precalculus TE accessibility (#916)
* Merge in first prefigure branch * TE6 image * Remove cruft * TE6 image * TE1 images * Use angle-marker * TE5 diagrams * Missing diagram * Cleanup
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source/precalculus/source/08-TE/01.ptx

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For example, consider a point <m>P</m> on the unit circle, with coordinates <m>(x,y)</m>. If we draw a right triangle (as shown in the figure below), the Pythagorean Theorem says that <m>x^2+y^2=1</m>.
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<figure xml:id="Deriving-Pythagorean-Identity">
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<image>
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<sageplot>
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p=circle ((0,0), 1)
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p += line([(0,0),(.707,.707), (.707,0), (0,0)],thickness=3,color="black",ticks=[SR(1),SR(1)])
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p += text("$x$", (0.3,-0.1),color="black", fontsize=14)
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p += text("$y$", (.8, 0.4), color="black",fontsize=14)
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p += text("$P=(x,y)$", (.9, .8), color="black",fontsize=14)
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p += text("$1$", (.3, .4), color="black",fontsize=14)
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p.axes(True)
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p
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</sageplot>
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<prefigure xmlns="https://prefigure.org" label="prefigure-graph-te1-unit-circle">
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<xi:include href="prefigure/TE1-unit-circle.xml"/>
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</prefigure>
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</image>
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</figure>
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But, remember, that the <m>x</m>-coordinate of the point corresponds to <m>\cos\theta</m> and the <m>y</m>-coordinate corresponds to <m>\sin\theta</m>. Thus, we get: <me>\sin^2\theta + \cos^2\theta = 1</me>. Pythagorean Identities are used in solving many trigonometric problems where one trigonometric ratio is given and we are expected to find the other trigonometric ratios. The next two activities will lead us to find the other two Pythagorean Identities.
@@ -290,42 +283,16 @@ p
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</p>
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<figure>
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<sidebyside widths="50% 50%">
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<image>
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<sageplot>
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beta=pi/8
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alpha=3*pi/4
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q=plot([],aspect_ratio=1,ticks=[[],[]])
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q+=circle((0,0),1,color="#ddd")
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q+=line([(0,0),(cos(beta),sin(beta))],color="blue",thickness=2)
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q+=arc((0,0),0.2,sector=(0,beta),color="black")
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q+=text(r"$\beta$", (0.3*cos(beta/2),0.3*sin(beta/2)),color="black",fontsize=14)
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q+=line([(0,0),(cos(alpha),sin(alpha))],color="blue",thickness=2)
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q+=arc((0,0),0.15,sector=(0,alpha),color="black")
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q+=text(r"$\alpha$", (0.2*cos(alpha/2),0.2*sin(alpha/2)),color="black",fontsize=14)
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q+=line([(cos(beta),sin(beta)),(cos(alpha),sin(alpha))],color="blue",thickness=2)
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q+=text(r"$P$",(1.1*cos(alpha),1.1*sin(alpha)),color="black",fontsize=14)
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q+=text(r"$Q$",(1.1*cos(beta),1.1*sin(beta)),color="black",fontsize=14)
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q+=text(r"$O$",(-0.1,-0.1),color="black",fontsize=14)
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q
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</sageplot>
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</image>
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<image>
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<sageplot>
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beta=pi/8
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alpha=3*pi/4
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p=plot([],aspect_ratio=1,ticks=[[],[]])
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p+=circle((0,0),1,color="#ddd")
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p+=line([(0,0),(cos(0),sin(0))],color="blue",thickness=2)
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p+=line([(0,0),(cos(alpha-beta),sin(alpha-beta))],color="blue",thickness=2)
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p+=arc((0,0),0.1,sector=(0,alpha-beta),color="black")
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p+=text(r"$\alpha-\beta$", (0.15*cos((alpha-beta)/2)+0.1,0.15*sin((alpha-beta)/2)),color="black",fontsize=14)
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p+=line([(cos(alpha-beta),sin(alpha-beta)),(cos(0),sin(0))],color="blue",thickness=2)
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p+=text(r"$A$",(1.1*cos(alpha-beta),1.1*sin(alpha-beta)),color="black",fontsize=14)
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p+=text(r"$B$",(1.1*cos(0),1.1*sin(0)+0.05),color="black",fontsize=14)
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p+=text(r"$O$",(-0.1,-0.1),color="black",fontsize=14)
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p
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</sageplot>
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</image>
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<image>
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<prefigure xmlns="https://prefigure.org" label="prefigure-graph-TE1-difference1">
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<xi:include href="prefigure/TE1-difference-1.xml"/>
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</prefigure>
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</image>
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<image>
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<prefigure xmlns="https://prefigure.org" label="prefigure-graph-TE1-difference2">
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<xi:include href="prefigure/TE1-difference-2.xml"/>
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</prefigure>
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</image>
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</sidebyside>
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<caption>Triangle <m>POQ</m> and its rotation clockwise by <m>\beta</m>, Triangle <m>AOB</m> </caption>
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</figure>

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