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1142-UserActivityForThePast30DaysII.sql
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83 lines (78 loc) · 4.66 KB
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-- 1142. User Activity for the Past 30 Days II
-- Table: Activity
-- +---------------+---------+
-- | Column Name | Type |
-- +---------------+---------+
-- | user_id | int |
-- | session_id | int |
-- | activity_date | date |
-- | activity_type | enum |
-- +---------------+---------+
-- This table may have duplicate rows.
-- The activity_type column is an ENUM (category) of type ('open_session', 'end_session', 'scroll_down', 'send_message').
-- The table shows the user activities for a social media website.
-- Note that each session belongs to exactly one user.
-- Write a solution to find the average number of sessions per user for a period of 30 days ending 2019-07-27 inclusively, rounded to 2 decimal places.
-- The sessions we want to count for a user are those with at least one activity in that time period.
-- The result format is in the following example.
-- Example 1:
-- Input:
-- Activity table:
-- +---------+------------+---------------+---------------+
-- | user_id | session_id | activity_date | activity_type |
-- +---------+------------+---------------+---------------+
-- | 1 | 1 | 2019-07-20 | open_session |
-- | 1 | 1 | 2019-07-20 | scroll_down |
-- | 1 | 1 | 2019-07-20 | end_session |
-- | 2 | 4 | 2019-07-20 | open_session |
-- | 2 | 4 | 2019-07-21 | send_message |
-- | 2 | 4 | 2019-07-21 | end_session |
-- | 3 | 2 | 2019-07-21 | open_session |
-- | 3 | 2 | 2019-07-21 | send_message |
-- | 3 | 2 | 2019-07-21 | end_session |
-- | 3 | 5 | 2019-07-21 | open_session |
-- | 3 | 5 | 2019-07-21 | scroll_down |
-- | 3 | 5 | 2019-07-21 | end_session |
-- | 4 | 3 | 2019-06-25 | open_session |
-- | 4 | 3 | 2019-06-25 | end_session |
-- +---------+------------+---------------+---------------+
-- Output:
-- +---------------------------+
-- | average_sessions_per_user |
-- +---------------------------+
-- | 1.33 |
-- +---------------------------+
-- Explanation: User 1 and 2 each had 1 session in the past 30 days while user 3 had 2 sessions so the average is (1 + 1 + 2) / 3 = 1.33.
-- Create table If Not Exists Activity (user_id int, session_id int, activity_date date, activity_type ENUM('open_session', 'end_session', 'scroll_down', 'send_message'))
-- Truncate table Activity
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'open_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'scroll_down')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('1', '1', '2019-07-20', 'end_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-20', 'open_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-21', 'send_message')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('2', '4', '2019-07-21', 'end_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'open_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'send_message')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '2', '2019-07-21', 'end_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'open_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'scroll_down')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('3', '5', '2019-07-21', 'end_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('4', '3', '2019-06-25', 'open_session')
-- insert into Activity (user_id, session_id, activity_date, activity_type) values ('4', '3', '2019-06-25', 'end_session')
-- # Write your MySQL query statement below
SELECT
IFNULL(
ROUND(
COUNT(DISTINCT session_id) / COUNT(DISTINCT user_id),
2
),
0
) AS average_sessions_per_user
FROM
Activity
WHERE
DATEDIFF('2019-07-27', activity_date) < 30
-- ROUND(x, d): 四舍五入保留 x 的 d 位小数。
-- IFNULL(x1, x2) :如果 x1 为 NULL, 返回 x2
-- 计算两个日期之间的天数差:
-- TIMESTAMPDIFF(DAY, CURRENT_DATE(), '2024-01-01');