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1748-SumOfUniqueElements.go
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59 lines (50 loc) · 1.49 KB
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package main
// 1748. Sum of Unique Elements
// You are given an integer array nums.
// The unique elements of an array are the elements that appear exactly once in the array.
// Return the sum of all the unique elements of nums.
// Example 1:
// Input: nums = [1,2,3,2]
// Output: 4
// Explanation: The unique elements are [1,3], and the sum is 4.
// Example 2:
// Input: nums = [1,1,1,1,1]
// Output: 0
// Explanation: There are no unique elements, and the sum is 0.
// Example 3:
// Input: nums = [1,2,3,4,5]
// Output: 15
// Explanation: The unique elements are [1,2,3,4,5], and the sum is 15.
// Constraints:
// 1 <= nums.length <= 100
// 1 <= nums[i] <= 100
import "fmt"
func sumOfUnique(nums []int) int {
res, mp := 0, make(map[int]int)
for _, v := range nums {
mp[v]++
}
for k, v := range mp {
if v == 1 { // unique element
res += k
}
}
return res
}
func main() {
// Example 1:
// Input: nums = [1,2,3,2]
// Output: 4
// Explanation: The unique elements are [1,3], and the sum is 4.
fmt.Println(sumOfUnique([]int{1,2,3,2})) // 4
// Example 2:
// Input: nums = [1,1,1,1,1]
// Output: 0
// Explanation: There are no unique elements, and the sum is 0.
fmt.Println(sumOfUnique([]int{1,1,1,1,1})) // 0
// Example 3:
// Input: nums = [1,2,3,4,5]
// Output: 15
// Explanation: The unique elements are [1,2,3,4,5], and the sum is 15.
fmt.Println(sumOfUnique([]int{1,2,3,4,5})) // 15
}