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2089-FindTargetIndicesAfterSortingArray.go
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72 lines (62 loc) · 2.03 KB
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package main
// 2089. Find Target Indices After Sorting Array
// You are given a 0-indexed integer array nums and a target element target.
// A target index is an index i such that nums[i] == target.
// Return a list of the target indices of nums after sorting nums in non-decreasing order.
// If there are no target indices, return an empty list.
// The returned list must be sorted in increasing order.
// Example 1:
// Input: nums = [1,2,5,2,3], target = 2
// Output: [1,2]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The indices where nums[i] == 2 are 1 and 2.
// Example 2:
// Input: nums = [1,2,5,2,3], target = 3
// Output: [3]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The index where nums[i] == 3 is 3.
// Example 3:
// Input: nums = [1,2,5,2,3], target = 5
// Output: [4]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The index where nums[i] == 5 is 4.
// Constraints:
// 1 <= nums.length <= 100
// 1 <= nums[i], target <= 100
import "fmt"
func targetIndices(nums []int, target int) []int {
less, equal := 0, 0
for _, v := range nums {
if v == target {
equal++
}
if v < target {
less++
}
}
res := make([]int, equal)
for i := 0; i < equal; i++ {
res[i] = i + less
}
return res
}
func main() {
// Example 1:
// Input: nums = [1,2,5,2,3], target = 2
// Output: [1,2]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The indices where nums[i] == 2 are 1 and 2.
fmt.Println(targetIndices([]int{1,2,5,2,3}, 2)) // [1,2]
// Example 2:
// Input: nums = [1,2,5,2,3], target = 3
// Output: [3]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The index where nums[i] == 3 is 3.
fmt.Println(targetIndices([]int{1,2,5,2,3}, 3)) // [3]
// Example 3:
// Input: nums = [1,2,5,2,3], target = 5
// Output: [4]
// Explanation: After sorting, nums is [1,2,2,3,5].
// The index where nums[i] == 5 is 4.
fmt.Println(targetIndices([]int{1,2,5,2,3}, 5)) // [4]
}