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2248-IntersectionOfMultipleArrays.go
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76 lines (67 loc) · 2.37 KB
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package main
// 2248. Intersection of Multiple Arrays
// Given a 2D integer array nums where nums[i] is a non-empty array of distinct positive integers,
// return the list of integers that are present in each array of nums sorted in ascending order.
// Example 1:
// Input: nums = [[3,1,2,4,5],[1,2,3,4],[3,4,5,6]]
// Output: [3,4]
// Explanation:
// The only integers present in each of nums[0] = [3,1,2,4,5], nums[1] = [1,2,3,4], and nums[2] = [3,4,5,6] are 3 and 4, so we return [3,4].
// Example 2:
// Input: nums = [[1,2,3],[4,5,6]]
// Output: []
// Explanation:
// There does not exist any integer present both in nums[0] and nums[1], so we return an empty list [].
// Constraints:
// 1 <= nums.length <= 1000
// 1 <= sum(nums[i].length) <= 1000
// 1 <= nums[i][j] <= 1000
// All the values of nums[i] are unique.
import "fmt"
import "sort"
func intersection(nums [][]int) []int {
n, res, m := len(nums), []int{}, make(map[int]int)
for i := 0; i < n; i++ { // 遍历所有数组写到 map 中
for j := 0; j < len(nums[i]); j++ {
m[nums[i][j]]++
}
}
for k, v := range m {
if v == n { // 所有数组存在
res = append(res, k)
}
}
sort.Ints(res)
return res
}
// 使用数组
func intersection1(nums [][]int) []int {
n, res, arr := len(nums), []int{}, make([]int, 1001) // 1 <= nums[i][j] <= 1000
for _, rows := range nums {
for _, v := range rows {
arr[v]++
}
}
for k, v := range arr {
if v == n { // 所有数组存在
res = append(res, k)
}
}
return res
}
func main() {
// Example 1:
// Input: nums = [[3,1,2,4,5],[1,2,3,4],[3,4,5,6]]
// Output: [3,4]
// Explanation:
// The only integers present in each of nums[0] = [3,1,2,4,5], nums[1] = [1,2,3,4], and nums[2] = [3,4,5,6] are 3 and 4, so we return [3,4].
fmt.Println(intersection([][]int{{3,1,2,4,5},{1,2,3,4},{3,4,5,6}})) // [3,4]
// Example 2:
// Input: nums = [[1,2,3],[4,5,6]]
// Output: []
// Explanation:
// There does not exist any integer present both in nums[0] and nums[1], so we return an empty list [].
fmt.Println(intersection([][]int{{1,2,3},{4,5,6}})) // []
fmt.Println(intersection1([][]int{{3,1,2,4,5},{1,2,3,4},{3,4,5,6}})) // [3,4]
fmt.Println(intersection1([][]int{{1,2,3},{4,5,6}})) // []
}