2432-TheEmployeeThatWorkedOnTheLongestTask.go

package main

// 2432. The Employee That Worked on the Longest Task
// There are n employees, each with a unique id from 0 to n - 1.

// You are given a 2D integer array logs where logs[i] = [idi, leaveTimei] where:
//     idi is the id of the employee that worked on the ith task, and
//     leaveTimei is the time at which the employee finished the ith task. All the values leaveTimei are unique.

// Note that the ith task starts the moment right after the (i - 1)th task ends, and the 0th task starts at time 0.

// Return the id of the employee that worked the task with the longest time. 
// If there is a tie between two or more employees, return the smallest id among them.

// Example 1:
// Input: n = 10, logs = [[0,3],[2,5],[0,9],[1,15]]
// Output: 1
// Explanation: 
// Task 0 started at 0 and ended at 3 with 3 units of times.
// Task 1 started at 3 and ended at 5 with 2 units of times.
// Task 2 started at 5 and ended at 9 with 4 units of times.
// Task 3 started at 9 and ended at 15 with 6 units of times.
// The task with the longest time is task 3 and the employee with id 1 is the one that worked on it, so we return 1.

// Example 2:
// Input: n = 26, logs = [[1,1],[3,7],[2,12],[7,17]]
// Output: 3
// Explanation: 
// Task 0 started at 0 and ended at 1 with 1 unit of times.
// Task 1 started at 1 and ended at 7 with 6 units of times.
// Task 2 started at 7 and ended at 12 with 5 units of times.
// Task 3 started at 12 and ended at 17 with 5 units of times.
// The tasks with the longest time is task 1. The employee that worked on it is 3, so we return 3.

// Example 3:
// Input: n = 2, logs = [[0,10],[1,20]]
// Output: 0
// Explanation: 
// Task 0 started at 0 and ended at 10 with 10 units of times.
// Task 1 started at 10 and ended at 20 with 10 units of times.
// The tasks with the longest time are tasks 0 and 1. The employees that worked on them are 0 and 1, so we return the smallest id 0.

// Constraints:
//     2 <= n <= 500
//     1 <= logs.length <= 500
//     logs[i].length == 2
//     0 <= idi <= n - 1
//     1 <= leaveTimei <= 500
//     idi != idi+1
//     leaveTimei are sorted in a strictly increasing order.

import "fmt"

func hardestWorker(n int, logs [][]int) int {
    id, mx := logs[0][0], logs[0][1]
    for i := 1; i < len(logs); i++ {
        v := logs[i][1] - logs[i - 1][1]
        if v > mx {
            mx, id = v, logs[i][0]
        } else if v == mx && logs[i][0] < id {
            id = logs[i][0]
        }
    }
    return id
}

func main() {
    // Example 1:
    // Input: n = 10, logs = [[0,3],[2,5],[0,9],[1,15]]
    // Output: 1
    // Explanation: 
    // Task 0 started at 0 and ended at 3 with 3 units of times.
    // Task 1 started at 3 and ended at 5 with 2 units of times.
    // Task 2 started at 5 and ended at 9 with 4 units of times.
    // Task 3 started at 9 and ended at 15 with 6 units of times.
    // The task with the longest time is task 3 and the employee with id 1 is the one that worked on it, so we return 1.
    fmt.Println(hardestWorker(10, [][]int{{0,3},{2,5},{0,9},{1,15}})) // 1
    // Example 2:
    // Input: n = 26, logs = [[1,1],[3,7],[2,12],[7,17]]
    // Output: 3
    // Explanation: 
    // Task 0 started at 0 and ended at 1 with 1 unit of times.
    // Task 1 started at 1 and ended at 7 with 6 units of times.
    // Task 2 started at 7 and ended at 12 with 5 units of times.
    // Task 3 started at 12 and ended at 17 with 5 units of times.
    // The tasks with the longest time is task 1. The employee that worked on it is 3, so we return 3.
    fmt.Println(hardestWorker(26, [][]int{{1,1},{3,7},{2,12},{7,17}})) // 3
    // Example 3:
    // Input: n = 2, logs = [[0,10],[1,20]]
    // Output: 0
    // Explanation: 
    // Task 0 started at 0 and ended at 10 with 10 units of times.
    // Task 1 started at 10 and ended at 20 with 10 units of times.
    // The tasks with the longest time are tasks 0 and 1. The employees that worked on them are 0 and 1, so we return the smallest id 0.
    fmt.Println(hardestWorker(2, [][]int{{0,10},{1,20}})) // 0
}