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739-DailyTemperatures.go
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66 lines (56 loc) · 2.04 KB
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package main
// 739. Daily Temperatures
// Given an array of integers temperatures represents the daily temperatures,
// return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature.
// If there is no future day for which this is possible, keep answer[i] == 0 instead.
// Example 1:
// Input: temperatures = [73,74,75,71,69,72,76,73]
// Output: [1,1,4,2,1,1,0,0]
// Example 2:
// Input: temperatures = [30,40,50,60]
// Output: [1,1,1,0]
// Example 3:
// Input: temperatures = [30,60,90]
// Output: [1,1,0]
// Constraints:
// 1 <= temperatures.length <= 10^5
// 30 <= temperatures[i] <= 100
import "fmt"
// 暴力解法
func dailyTemperatures(temperatures []int) []int {
res, j := make([]int, len(temperatures)), 0
for i := 0; i < len(temperatures); i++ {
// 从 i + 1 开始找
for j = i + 1; j < len(temperatures); j++ {
// 如果发现后面温度大于该天,计算之间相差天数
if temperatures[j] > temperatures[i] {
res[i] = j - i
break
}
}
}
return res
}
// 使用 stack
func dailyTemperatures1(temperatures []int) []int {
res := make([]int, len(temperatures))
stack := []int{}
for i, t := range temperatures {
for len(stack) > 0 && temperatures[stack[len(stack)-1]] < t {
// 维护一个单调递减的单调栈
index := stack[len(stack)-1]
res[index] = i - index
stack = stack[:len(stack)-1]
}
stack = append(stack, i)
}
return res
}
func main() {
fmt.Println(dailyTemperatures([]int{73,74,75,71,69,72,76,73})) // [1,1,4,2,1,1,0,0]
fmt.Println(dailyTemperatures([]int{30,40,50,60})) // [1,1,1,0]
fmt.Println(dailyTemperatures([]int{30,60,90})) // [1,1,0]
fmt.Println(dailyTemperatures1([]int{73,74,75,71,69,72,76,73})) // [1,1,4,2,1,1,0,0]
fmt.Println(dailyTemperatures1([]int{30,40,50,60})) // [1,1,1,0]
fmt.Println(dailyTemperatures1([]int{30,60,90})) // [1,1,0]
}