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747-LargestNumberAtLeastTwiceOfOthers.go
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58 lines (51 loc) · 1.66 KB
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package main
// 747. Largest Number At Least Twice of Others
// You are given an integer array nums where the largest integer is unique.
// Determine whether the largest element in the array is at least twice as much as every other number in the array.
// If it is, return the index of the largest element, or return -1 otherwise.
// Example 1:
// Input: nums = [3,6,1,0]
// Output: 1
// Explanation: 6 is the largest integer.
// For every other number in the array x, 6 is at least twice as big as x.
// The index of value 6 is 1, so we return 1.
// Example 2:
// Input: nums = [1,2,3,4]
// Output: -1
// Explanation: 4 is less than twice the value of 3, so we return -1.
// Constraints:
// 2 <= nums.length <= 50
// 0 <= nums[i] <= 100
// The largest element in nums is unique.
import "fmt"
func dominantIndex(nums []int) int {
res, mx := -1, 0
for i, v := range nums {
if v > mx { // 找到最大值
mx = v
res = i
}
}
for i, v := range nums { // 检查最大值是否都是大其它值的2倍
if res != i {
if mx < 2 * v {
return -1
}
}
}
return res
}
func main() {
// Example 1:
// Input: nums = [3,6,1,0]
// Output: 1
// Explanation: 6 is the largest integer.
// For every other number in the array x, 6 is at least twice as big as x.
// The index of value 6 is 1, so we return 1.
fmt.Println(dominantIndex([]int{3,6,1,0})) // 1
// Example 2:
// Input: nums = [1,2,3,4]
// Output: -1
// Explanation: 4 is less than twice the value of 3, so we return -1.
fmt.Println(dominantIndex([]int{1,2,3,4})) // -1
}