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LCR039-LargestRectangleInHistogram.go
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87 lines (78 loc) · 2.96 KB
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package main
// LCR 039. 柱状图中最大的矩形
// 给定非负整数数组 heights ,数组中的数字用来表示柱状图中各个柱子的高度。每个柱子彼此相邻,且宽度为 1 。
// 求在该柱状图中,能够勾勒出来的矩形的最大面积。
// 示例 1:
// <img src="https://assets.leetcode.com/uploads/2021/01/04/histogram.jpg" />
// 输入:heights = [2,1,5,6,2,3]
// 输出:10
// 解释:最大的矩形为图中红色区域,面积为 10
// 示例 2:
// <img src="https://assets.leetcode.com/uploads/2021/01/04/histogram-1.jpg" />
// 输入: heights = [2,4]
// 输出: 4
// 提示:
// 1 <= heights.length <=10^5
// 0 <= heights[i] <= 10^4
import "fmt"
// stack
func largestRectangleArea(heights []int) int {
res, n := 0, len(heights) + 2
// Add a sentry at the beginning and the end
getHeight := func(i int) int { if i == 0 || n-1 == i { return 0; }; return heights[i-1]; }
max := func (x, y int) int { if x > y { return x; }; return y; }
stack := make([]int, 0, n/2)
for i := 0; i < n; i++ {
for len(stack) > 0 && getHeight(stack[len(stack) - 1]) > getHeight(i) {
// pop stack
idx := stack[len(stack)-1]
stack = stack[:len(stack)-1]
res = max(res, getHeight(idx)*(i- stack[len(stack) -1 ] - 1))
}
// push stack
stack = append(stack, i)
}
return res
}
// dp
func largestRectangleArea1(heights []int) int {
l := len(heights)
if l == 0 {
return 0
}
left, right:= make([]int, l), make([]int, l)
for i := 1 ; i < l; i++ {
left[i] = i
j := i
for left[j] - 1 >= 0 && heights[left[j] - 1] >= heights[i] {
j = left[j] - 1
}
left[i] = left[j]
}
right[l - 1] = l - 1
for i := l - 2; i >= 0; i-- {
right[i] = i
j := i
for right[j] + 1 <= l - 1 && heights[right[j] + 1] >= heights[i] {
j = right[j] + 1
}
right[i] = right[j]
}
res := 0
for i := 0; i < l; i++ {
if heights[i] * (right[i] - left[i] + 1) > res {
res = heights[i] * (right[i] - left[i] + 1)
}
}
return res
}
func main() {
// Explanation: The above is a histogram where width of each bar is 1.
// The largest rectangle is shown in the red area, which has an area = 10 units.
fmt.Printf("largestRectangleArea([]int{2,1,5,6,2,3}) = %v\n",largestRectangleArea([]int{2,1,5,6,2,3})) // 10
fmt.Printf("largestRectangleArea([]int{2,4}) = %v\n",largestRectangleArea([]int{2,4})) // 4
fmt.Printf("largestRectangleArea([]int{2,3}) = %v\n",largestRectangleArea([]int{2,3})) // 4
fmt.Printf("largestRectangleArea1([]int{2,1,5,6,2,3}) = %v\n",largestRectangleArea1([]int{2,1,5,6,2,3})) // 10
fmt.Printf("largestRectangleArea1([]int{2,4}) = %v\n",largestRectangleArea1([]int{2,4})) // 4
fmt.Printf("largestRectangleArea1([]int{2,3}) = %v\n",largestRectangleArea1([]int{2,3})) // 4
}