Go: skip extracting ast.ParenExpr nodes

Instead of creating a database entry for parenthesised expressions,
extract their child expression directly in their place. This makes the
extracted AST act as if ParenExpr nodes do not exist while still
correctly extracting children.

Co-authored-by: Copilot <223556219+Copilot@users.noreply.github.com>

Author: owen-mc

go/extractor/extractor.go

@@ -1013,6 +1013,12 @@ func extractExpr(tw *trap.Writer, expr ast.Expr, parent trap.Label, idx int, ski
 		return
 	}
 
+	// Skip parenthesised expressions and extract their child directly in their place
+	if paren, ok := expr.(*ast.ParenExpr); ok {
+		extractExpr(tw, paren.X, parent, idx, skipExtractingValue)
+		return
+	}
+
 	lbl := tw.Labeler.LocalID(expr)
 	extractTypeOf(tw, expr, lbl)
 
@@ -1087,9 +1093,6 @@ func extractExpr(tw *trap.Writer, expr ast.Expr, parent trap.Label, idx int, ski
 		kind = dbscheme.CompositeLitExpr.Index()
 		extractExpr(tw, expr.Type, lbl, 0, false)
 		extractExprs(tw, expr.Elts, lbl, 1, 1)
-	case *ast.ParenExpr:
-		kind = dbscheme.ParenExpr.Index()
-		extractExpr(tw, expr.X, lbl, 0, false)
 	case *ast.SelectorExpr:
 		kind = dbscheme.SelectorExpr.Index()
 		extractExpr(tw, expr.X, lbl, 0, false)