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0698-partition-to-k-equal-sum-subsets.py
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42 lines (29 loc) · 1.04 KB
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class Solution(object):
def canPartitionKSubsets(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: bool
"""
if sum(nums) % k != 0:
return False
nums.sort(reverse = True)
target = sum(nums) / k
visited= set()
def backtrack(idx, count, currSum):
if count == k:
return True
if target == currSum:
return backtrack(0, count + 1, 0)
for i in range(idx, len(nums)):
# skip duplicates if last same number was skipped
if i > 0 and (i - 1) not in visited and nums[i] == nums[i - 1]:
continue
if i in visited or currSum + nums[i] > target:
continue
visited.add(i)
if backtrack(i + 1, count, currSum + nums[i]):
return True
visited.remove(i)
return False
return backtrack(0, 0, 0)