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Manifold with boundary and related properties (part 2)
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properties/P000122.md

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---
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Each point has a neighborhood homeomorphic to an open subset of $\mathbb R^n$
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with its Euclidean topology for some $n\ge 0$. Equivalently, each point has a neighborhood
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with its Euclidean topology for some integer $n\ge 0$. Equivalently, each point has a neighborhood
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homeomorphic to $\mathbb R^n$ for some $n$. Note that the value of $n$ is allowed
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to differ between points; if it does not vary, then the space has the stronger
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property {P123}.
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In the case that $n=0$, the point having a neighborhood homeomorphic to
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$\mathbb R^0=\{0\}$ means it is an isolated point.
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In the case $n=0$, a point with a neighborhood homeomorphic to
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$\mathbb R^0=\{0\}$ is an isolated point.
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*Note*: In all the above, one can equivalently require the neighborhoods to be open.
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properties/P000206.md

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of this game, Player 1 chooses a point $x_n$ with an open neighborhood $U_n\subseteq V_{n-1}$,
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and Player 2 chooses some open neighborhood $V_n\subseteq U_n$ of $x_n$.
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Player 2 wins this game provided $\bigcap\{U_n:n<\omega\}\not=\emptyset$.
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Player 2 wins this game provided
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$\bigcap\{U_n:n<\omega\}\; (= \bigcap\{V_n:n<\omega\}) \not=\emptyset$.
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Note: We consider the {P137} space to be {P206} in the sense that
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Player 1 cannot make a legal move to start the game, and therefore loses immediately according

theorems/T000082.md

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---
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uid: T000082
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if:
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P000122: true
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P000235: true
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then:
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P000096: true
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---
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Every point $x\in X$ has an open neighborhood $U$ homeomorphic to some $\mathbb R^n$.
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The open balls centered at $x$ within $U$
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Every point $x\in X$ has an open neighborhood $U$ homeomorphic to some $\mathbb R^n_+$.
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The open balls centered at $x$ within the metric space $U$
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(identified with a subset of $\mathbb R^n_+$)
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form a local base of neighborhoods open in $X$ and {P95}.

theorems/T000171.md

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uid: T000171
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if:
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and:
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- P000122: true
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- P000235: true
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- P000125: true
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then:
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P000039: false
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refs:
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- zb: "0951.54001"
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name: Topology (Munkres)
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---
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If there is a point $x\in X$ that has an open neighborhood $U$ homeomorphic to
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$\mathbb R^n$ with $n\ge 1$, the open set $U$ contains two disjoint
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If some point $x\in X$ has an open neighborhood $U$ homeomorphic to
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$\mathbb R^n$ or $\mathbb R^n_+$ with $n\ge 1$, the open set $U$ contains two disjoint
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nonempty open sets, themselves open in $X$. Otherwise, every point is isolated;
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so two distinct points are contained in two disjoint nonempty open sets.

theorems/T000172.md

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---
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uid: T000172
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if:
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P000122: true
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P000235: true
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then:
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P000206: true
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---
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Player 2 can choose a neighborhood $V_0$ that is homeomorphic to some $\mathbb R^n$.
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Then the game is played on $\mathbb R^n$ and Player 2 can win because $\mathbb R^n$ is {P206} [(Explore)](https://topology.pi-base.org/spaces?q=Completely+metrizable+%2B+%7EEmpty+%2B+%7EStrongly+Choquet).
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After Player 1 chooses an open set $U_0$ and a point $x_0\in U_0$,
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Player 2 can choose a open neighborhood $V_0\subseteq U_0$ of $x_0$
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with $V_0$ homeomorphic to some $\mathbb R^n$ or $\mathbb R^n_+$.
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The rest of the game is played on $V_0$ and Player 2 has a winning strategy
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since $\mathbb R^n$ and $\mathbb R^n_+$ are both {P206}
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[(Explore)](https://topology.pi-base.org/spaces?q=Completely+metrizable+%2B+%7EStrongly+Choquet).

theorems/T000175.md

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uid: T000175
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if:
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and:
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- P000122: true
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- P000235: true
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- P000018: true
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then:
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P000027: true
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refs:
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- mathse: 4416020
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name: Lindelof and locally Euclidean implies second countable
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---
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See {{mathse:4416020}}.
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Apply the argument in {{mathse:4416020}},
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using the fact that both $\mathbb R^n$ and $\mathbb R^n_+$ are {P27}.

theorems/T000329.md

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---
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uid: T000329
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if:
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P000122: true
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P000235: true
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then:
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P000082: true
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refs:
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- zb: "0951.54001"
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name: Topology (Munkres)
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---
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Every point has a neighborhood that is homeomorphic to an open subset of some $\mathbb R^n$, hence {P53}. See Exercise 1 on p. 317 of {{zb:0951.54001}}.
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Every point has a neighborhood homeomorphic to some $\mathbb R^n_+$, hence {P53}.

theorems/T000332.md

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---
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uid: T000332
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if:
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P000122: true
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P000235: true
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then:
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P000130: true
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refs:
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- mathse: 103774
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name: Every manifold is locally compact?
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---
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Every point has a neighborhood that is homeomorphic to $\mathbb R^n$ for some non-negative integer $n$. Since $\mathbb R^n$ is {P130}, it produces a local base of compact sets.
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Every point $p$ has a neighborhood $U$ homeomorphic to some $\mathbb R^n_+$.
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Since $\mathbb R^n_+$ is {P130}, $p$ has a local base of compact neighborhoods in $U$,
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which also form a local base in $X$.

theorems/T000438.md

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uid: T000438
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if:
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and:
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- P000123: true
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- P000236: true
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- P000139: true
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then:
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P000052: true
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---
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A point is isolated iff it has a neighborhood homeomorphic to $\mathbb R^0$.
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A point is isolated iff it has a neighborhood homeomorphic to $\mathbb R^0_+=\mathbb R^0=\{0\}$.
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So if this holds for one point, it holds for all the points and the space is {P52}.

theorems/T000537.md

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uid: T000537
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if:
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and:
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- P000122: true
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- P000235: true
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- P000086: true
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then:
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P000123: true
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---
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If one point has a neighborhood homeomorphic to $\mathbb R^n$ for some $n$,
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then all points do with the same $n$ via self-homeomorphisms of the space.
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If one point $x$ has an open neighborhood $U$ homeomorphic to some $\mathbb R^n_+$,
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some point (maybe different from $x$) in $U$ has a neighborhood homeomorphic to $\mathbb R^n$.
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By homomogeneity, every point has a neighborhood homeomorphic to $\mathbb R^n$.

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