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Intermediate_SQL Joins_Practice.sql
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72 lines (50 loc) · 1.81 KB
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/*
Inner Joins, Full/Left/Right/Outer Joins
*/
SELECT *
FROM EmployeeDemographics
SELECT *
FROM EmployeeSalary
INSERT INTO EmployeeSalary VALUES
(1010, NULL, 47000),
(NULL,'Salesman',43000)
-- AT THE TOP I INSERTED MISSING NULL VALUES TO THE DATA TO START PRACTICING
--NOW I WILL START JOINING THE DATA
SELECT *
FROM EmployeeDemographics
INNER JOIN EmployeeSalary
ON EmployeeDemographics.EmployeeID = EmployeeSalarY.EmployeeID
-- OUTER JOIN FUll
SELECT *
FROM EmployeeDemographics
FULL Outer Join EmployeeSalary
ON EmployeeDemographics.EmployeeID = EmployeeSalarY.EmployeeID
-- Left Outer Join/ Left Join
SELECT *
FROM EmployeeDemographics
Right Outer Join EmployeeSalary
ON EmployeeDemographics.EmployeeID = EmployeeSalary.EmployeeID
-- Joining using selected fields in the SELECT statement
SELECT EmployeeSalary.EmployeeID, FirstName, LastName, JobTitle, Salary
FROM EmployeeDemographics
Right Outer Join EmployeeSalary
On EmployeeDemographics.EmployeeID = EmployeeSalary.EmployeeID
SELECT EmployeeDemographics.EmployeeID, FirstName, LastName, JobTitle, Salary
FROM EmployeeDemographics
Left Outer Join EmployeeSalary
On EmployeeDemographics.EmployeeID = EmployeeSalary.EmployeeID
-- NOW CHECKING WHO HAS THE HIGHEST SALARY AND DEDUCT 1000 FROM IT
SELECT EmployeeDemographics.EmployeeID, FirstName, LastName, Salary
FROM EmployeeDemographics
INNER JOIN EmployeeSalary
ON EmployeeDemographics.EmployeeID = EmployeeSalary.EmployeeID
WHERE FirstName <> 'Michael'
ORDER BY Salary DESC
-- Another use case -- AVG salesman salary
SELECT JobTitle, AVG(Salary) AS avg_sal
From EmployeeDemographics
INNER JOIN EmployeeSalary
ON EmployeeDemographics.EmployeeID = EmployeeSalary.EmployeeID
WHERE JobTitle = 'Salesman'
GROUP BY JobTitle
ORDER BY avg_sal;