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65 changes: 65 additions & 0 deletions helloworld/H10_E1.c
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//1. Rewrite the program in Listing 10.1. This time, use the logical expression
//i%6 ==0 in the if statement.
#include <stdio.h>
main() {
setbuf(stdout, NULL);
printf("1. feladat. \n");
int i;
printf("Integers that can be divided by both 2 and 3\n");
printf("(within the range of 0 to 100):\n");
for (i=0; i<=100; i++) {
if (i % 6 == 0) {
printf(" %d\n", i);
}
}

//2. Rewrite the program in Listing 10.1 by using nested if statements.

printf("2. feladat. \n");
//int i; ha önálló progi lenne, kellene
printf("Integers that can be divided by both 2 and 3\n");
printf("(within the range of 0 to 100):\n");
for (i=0; i<=100; i++) {
if (i % 2 == 0) {
if (i % 3 == 0) {
printf(" %d\n", i);
}
}
}

//3. Write a program to read characters from the standard I/O. If the characters
// are A, B,and C, display their numeric values on the screen.
// (The switch statement is required.)
printf("3. feladat. \n");
char ch = '0';
printf("Please type in one character:\n");
ch = getc(stdin);
switch (ch) {
case 'A':
printf("A kódja: %d\n", ch);
break;
case 'B':
printf("B kódja: %d\n", ch);
break;
case 'C':
printf("C kódja: %d\n", ch);
break;
default:;
}
//4. Write a program that keeps reading characters from the standard input until
//the character q is entered.
printf("4. feladat. \n");
printf("Ezt a feladatot a 8. leckénél megoldottuk már :-)\n");

//5. Rewrite the program in Listing 10.7. This time, instead of skipping 3 and 5,
//skip the integer that can be evenly divided by both 2 and 3.
printf("5. feladat. \n");
int sum = 0;
for (i=1; i<8; i++) {
if ((i % 2 ==0) || (i % 3 ==0))
continue;
sum += i;
}
printf("The sum of 1, 5, and 7 is: %d\n", sum);
return 0;
}
51 changes: 51 additions & 0 deletions helloworld/H8_E1.c
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//1. Given x = 0xEFFF and y = 0x1000 (that is, EFFF and 1000 as hex values), what
//hex values do you get by evaluating ~x and ~y?
//
// Egymás ellentettjei, ezt már tisztáztuk :-)

//2. Taking the values of x and y assigned in Exercise 1, write a program that prints
//out the values of !x and !y by using both the %d and %u formats in the printf()
//function.

#include <stdio.h>

main() {
setbuf(stdout, NULL);
printf("2. feladat. \n");
int x = 0xEFFF;
int y = 0x1000;
printf("The values of !x and !y is: %d, %d\n", !x, !y);
printf("The values of !x and !y is: %u, %u\n", !x, !y);

// Na, hogy ennek mi értelme volt :-(

//3. Given x = 123 and y = 4, write a program that displays the results of the
//expressions x << y and x >> y.
printf("3. feladat. \n");
x = 123;
y = 4;
printf("The values of x << y is: %d\n", x << y);
printf("The values of x >> y is: %d\n", x >> y);



//4. Write a program that shows the values (in hex) of the expressions 0xFFFF^0x8888,
//0xABCD & 0x4567, and 0xDCBA | 0x1234.

printf("4. feladat. \n");
printf("The value of the expressions 0xFFFF^0x8888 is: %X\n", 0xFFFF^0x8888);
printf("The value of the expressions 0xABCD & 0x4567 is: %X\n", 0xABCD & 0x4567);
printf("The value of the expressions 0xDCBA | 0x1234 is: %X\n", 0xDCBA | 0x1234);

//5. Use the ?: operator and the for statement to write a program that keeps taking the
//characters entered by the user until the character q is accounted. (Hint: Put x!=’q’
//? 1 : 0 expression as the second expression in a for statement.)

printf("5. feladat. \n");
char ch = '0';
printf("Please type in one character:\n");
for (int i=0; ch!='q' ? 1 : 0;) {
ch = getc(stdin);
}
return 0;
}
57 changes: 57 additions & 0 deletions helloworld/H9_E1.c
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//1. Given the following statements,
//int x;
//unsigned int y;
//x = 0xAB78;
//y = 0xAB78;
//write a program to display the decimal values of x and y on the screen.

#include <stdio.h>
#include <math.h>
main() {
setbuf(stdout, NULL);
printf("1. feladat. \n");
int x;
unsigned int y;
x = 0xAB78;
y = 0xAB78;
printf("The decimal values of 0xAB78 is: %d\n", x);
printf("The decimal values of 0xAB78 is: %d\n", y);

//2. Write a program to measure the sizes of short int, long int, and long double
//on your machine.

printf("2. feladat. \n");
printf("The size of short int is: %d.\n", sizeof(short int));
printf("The size of long int is: %d.\n", sizeof(long int));
printf("The size of long double is: %d.\n", sizeof(long double));

//3. Write a program to multiply two signed int variables with positive values, and
//display the result as a long int.

printf("3. feladat. \n");

int a = 12;
int b = 84512;
printf("The productum of the variables is: %ld\n", a * b);

//4. Write a program to display negative integers in hex format along with their signed int equivalents.

printf("4. feladat. \n");
int neg_num = -1;
printf("Please type in one negative number:\n");
scanf ("%d", &neg_num);
printf("%x equal %d\n", neg_num, neg_num);

//5. Given an angle of 30 degrees, write a program to calculate its sine and tangentvalues.

printf("5. feladat. \n");
double angle = 30;
angle *= 3.141593 / 180.0;
printf("The sine of angle 30degree is %f, the tangent of it is: %f\n", sin(angle), tan(angle));

//6. Write a program to calculate the non-negative square root of 0x19A1.
printf("6. feladat. \n");
int hex = 0x19A1;
printf("The square root of 0x19A1 is: %f\n",sqrt(hex));
return 0;
}