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163 changes: 163 additions & 0 deletions lab.sql
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-- ============================================================
-- EXERCISE 1: Blog Database (Normalized to 3NF)
-- ============================================================

CREATE TABLE authors (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(100) NOT NULL UNIQUE
);

CREATE TABLE posts (
id INT PRIMARY KEY AUTO_INCREMENT,
author_id INT NOT NULL,
title VARCHAR(255) NOT NULL,
word_count INT NOT NULL CHECK (word_count > 0),
views INT NOT NULL DEFAULT 0 CHECK (views >= 0),
FOREIGN KEY (author_id) REFERENCES authors(id)
);

-- Sample Data - Exercise 1
INSERT INTO authors (name) VALUES
('Maria Charlotte'),
('Juan Perez'),
('Gemma Alcocer');

INSERT INTO posts (author_id, title, word_count, views) VALUES
(1, 'Best Paint Colors', 814, 14),
(2, 'Small Space Decorating Tips', 1146, 221),
(1, 'Hot Accessories', 986, 105),
(1, 'Mixing Textures', 765, 22),
(2, 'Kitchen Refresh', 1242, 307),
(1, 'Homemade Art Hacks', 1002, 193),
(3, 'Refinishing Wood Floors', 1571, 7542);


-- ============================================================
-- EXERCISE 2: Airline Database (Normalized to 3NF)
-- ============================================================

CREATE TABLE aircrafts (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(100) NOT NULL UNIQUE,
total_seats INT NOT NULL CHECK (total_seats > 0)
);

CREATE TABLE flights (
flight_number VARCHAR(10) PRIMARY KEY,
aircraft_id INT NOT NULL,
mileage INT NOT NULL CHECK (mileage > 0),
FOREIGN KEY (aircraft_id) REFERENCES aircrafts(id)
);

CREATE TABLE customers (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(100) NOT NULL UNIQUE,
status ENUM('None', 'Silver', 'Gold') NOT NULL DEFAULT 'None',
total_mileage INT NOT NULL DEFAULT 0 CHECK (total_mileage >= 0)
);

CREATE TABLE bookings (
id INT PRIMARY KEY AUTO_INCREMENT,
customer_id INT NOT NULL,
flight_number VARCHAR(10) NOT NULL,
FOREIGN KEY (customer_id) REFERENCES customers(id),
FOREIGN KEY (flight_number) REFERENCES flights(flight_number)
);

-- Sample Data - Exercise 2

INSERT INTO aircrafts (name, total_seats) VALUES
('Boeing 747', 400),
('Airbus A330', 236),
('Boeing 777', 264);

INSERT INTO flights (flight_number, aircraft_id, mileage) VALUES
('DL143', 1, 135),
('DL122', 2, 4370),
('DL53', 3, 2078),
('DL222', 3, 1765),
('DL37', 1, 531);

INSERT INTO customers (name, status, total_mileage) VALUES
('Agustine Riviera', 'Silver', 115235),
('Alaina Sepulvida', 'None', 6008),
('Tom Jones', 'Gold', 205767),
('Sam Rio', 'None', 2653),
('Jessica James', 'Silver', 127656),
('Ana Janco', 'Silver', 136773),
('Jennifer Cortez', 'Gold', 300582),
('Christian Janco', 'Silver', 14642);

INSERT INTO bookings (customer_id, flight_number) VALUES
(1, 'DL143'),
(1, 'DL122'),
(2, 'DL122'),
(1, 'DL143'),
(3, 'DL122'),
(3, 'DL53'),
(1, 'DL143'),
(4, 'DL143'),
(1, 'DL143'),
(3, 'DL222'),
(5, 'DL143'),
(4, 'DL143'),
(6, 'DL222'),
(7, 'DL222'),
(5, 'DL122'),
(4, 'DL37'),
(8, 'DL222');


-- ============================================================
-- EXERCISE 3: SQL Queries on the Airline Database
-- ============================================================

-- 1. Total number of flights
SELECT COUNT(DISTINCT flight_number) AS total_flights
FROM flights;

-- 2. Average flight distance
SELECT AVG(mileage) AS avg_flight_distance
FROM flights;

-- 3. Average number of seats per aircraft
SELECT AVG(total_seats) AS avg_seats_per_aircraft
FROM aircrafts;

-- 4. Average miles flown by customers, grouped by status
SELECT status, AVG(total_mileage) AS avg_mileage
FROM customers
GROUP BY status;

-- 5. Max miles flown by customers, grouped by status
SELECT status, MAX(total_mileage) AS max_mileage
FROM customers
GROUP BY status;

-- 6. Number of aircrafts with "Boeing" in their name
SELECT COUNT(*) AS boeing_count
FROM aircrafts
WHERE name LIKE '%Boeing%';

-- 7. Flights with distance between 300 and 2000 miles
SELECT *
FROM flights
WHERE mileage BETWEEN 300 AND 2000;

-- 8. Average flight distance booked, grouped by customer status
SELECT c.status, AVG(f.mileage) AS avg_booked_distance
FROM bookings b
JOIN customers c ON b.customer_id = c.id
JOIN flights f ON b.flight_number = f.flight_number
GROUP BY c.status;

-- 9. Most booked aircraft among Gold status members
SELECT a.name, COUNT(*) AS total_bookings
FROM bookings b
JOIN customers c ON b.customer_id = c.id
JOIN flights f ON b.flight_number = f.flight_number
JOIN aircrafts a ON f.aircraft_id = a.id
WHERE c.status = 'Gold'
GROUP BY a.name
ORDER BY total_bookings DESC
LIMIT 1;